How do you find the domain and range of sqrt(x^2 - 9)?

1 Answer
Jul 4, 2017

Domain = x
Range = x>=3

Explanation:

The domain is just the input, the variable=s) being changed. In thus case it is just x.

The range is the set of values of x which can plotted onto a graph. The lowest possible value for y is 0. So, 0=sqrt(x^2-9), 0=x^2-9, 9=x^2, x=sqrt(9)=3. sqrt(3^2-9)=sqrt(9-9)=sqrt(0)=0.