How do you find the domain and range of $y = 2 x^{2} - 5 x$ $y = 2x^2 - 5x$ ?

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Answer 1 · 2017-08-29T11:24:00

Domain: $x in RR or (-oo,oo)$ .
Range: $y >= -3.125 or [-3.125 , oo)$

$y=2x^2-5x$ . Domain : Any real value of x i.e $x in RR$

Range: $y= 2(x^2-5/2x) =2(x^2-5/2x + (5/4)^2) -2 *25/16$

$y = 2(x-5/4)^2 -25/8 = 2( x-1.25)^2 - 3.125$

Vertex is at $(1.25 , -3.125)$ , Range : $y >= -3.125$

Domain: $x in RR or (-oo,oo)$

Range: $y >= -3.125 or [-3.125 , oo)$

graph{2x^2-5x [-10, 10, -5, 5]}

How do you find the domain and range of y = 2x^2 - 5xy=2x2−5xy = 2x^2 - 5x?