How do you find the domain and range of $y = - 2 x^{2} - 8$ $y = -2x^2 - 8$ ?

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Answer 1 · 2015-09-17T15:37:24

The domain is $R$ $R$ and the range is hence

$y = - 2 x^{2} - 8 \leq - 8$ $y=-2x^2-8<=-8$ then range is $(- \infty, - 8]$ $(-oo,-8]$

How do you find the domain and range of y = -2x^2 - 8y=−2x2−8y = -2x^2 - 8?