How do you find the domain and range ofy = 3/ (x + 6) y=3x+6?

1 Answer
Mar 2, 2018

Domain: (-oo,-6)uu(-6,oo)(,6)(6,)

Range: (-oo,0)uu(0,oo)(,0)(0,)

Explanation:

The domain of a function is all possible values of x xwhere f(x)f(x) is defined. Here, when the denominator is equal to 0, the function is undefined. In this case:

x+6=0x+6=0

x=-6x=6

So yy is only undefined at x=-6x=6. In interval notation, we write the domain as (-oo,-6)uu(-6,oo)(,6)(6,).

The range of a function is all possible values for yy. Another way to solve for the range is to find y^-1y1, as in, the inverse function of yy, and find its domain. Here, we can find y^-1y1:

y=3/(x+6)y=3x+6

Switch the variables and solve for yy:

x=3/(y+6)x=3y+6

1/x=(y+6)/31x=y+63

3/x=y+63x=y+6

y=3/x-6y=3x6

This is y^-1y1. It is also defined when its denominator is equal to 00.

So y^-1y1 will be undefined when x=0x=0, and therefore yy will be undefined when y=0y=0. The range in interval notation is:

(-oo,0)uu(0,oo)(,0)(0,)