How do you find the domain and range of $y=5/(x-1)$ ?

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Answer 1 · 2016-12-24T14:19:10

The domain is $=RR-{1}$
The range is $=RR-{0}$

As you cannot divide by $0$ , $=>$ , $x!=1$

Therefore,

The domain of $x$ is $D_x=RR-{1}$

The limit of $y$ as $x->oo$ is

$lim_(x->-oo)y=lim_(x->-oo)5/x=0^(-)$

$lim_(x->+oo)y=lim_(x->+oo)5/x=0^(+)$

There is a horizontal asymptote at $y=0$

Therefore,

The range is $R_y =RR-{0}$

How do you find the domain and range of y=5/(x-1)y=5/(x-1)?