How do you find the domain and range of $y=5/(x-3)$ ?

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Answer 1 · 2018-06-06T15:31:00

The domain is $x in (-oo,3)uu(3,+oo)$ . The range is $y in (-oo,0)uu(0, oo)$ .

The denominator must be $!=0$ .

Therefore,

$x-3!=0$

$=>$ , $x!=3$

The domain is $x in (-oo,3)uu(3,+oo)$

To calculate the range, proceed as follows :

Let $y=(5)/(x-3)$

$y(x-3)=5$

$yx-3y=5$

$xy=5+3y$

$x=(5+3y)/(y)$

The denominator must be $!=0$ .

$y!=0$

The range is $y in (-oo,0)uu(0, oo)$

graph{5/(x-3) [-52, 52.03, -26, 26.03]}

How do you find the domain and range of y=5/(x-3)y=5/(x-3)?