How do you find the domain and range of $y = \sqrt{x - 1}$ $y = sqrt(x - 1)$ ?

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How do you find the domain and range of $y = \sqrt{x - 1}$ $y = sqrt(x - 1)$ ?

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Answer 1 · 2018-03-21T00:21:46

Domain- $1 \leq x <$ $1<=x<$ $\propto$ $prop$
Range- $0 \leq y <$ $0<=y<$ $\propto$ $prop$

Explanation:

$x$ $x$ cannot be $< 1$ $<1$ , because if $x < 1$ $x<1$ , there would be a negative under the radical, which cannot exist in the real number system. So $x$ $x$ can be anywhere from $1$ $1$ to $\propto$ $prop$ .

Since $x$ $x$ must be at least 1, the value of $y$ $y$ can range from $\sqrt{0}$ $sqrt0$ $= 0$ $=0$ , to $\sqrt{}$ $sqrt$ of any value $> x$ $>x$ , which makes the limit of the range $\propto$ $prop$ .

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How do you find the domain and range of $y = \sqrt{x - 1}$ $y = sqrt(x - 1)$ ?

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How do you find the domain and range of $y = \sqrt{x - 1}$ $y = sqrt(x - 1)$ ?