How do you find the domain and range of y = sqrt(x-10) + 5?

1 Answer

Refer to explanation

Explanation:

Well we have that

y=f(x)=sqrt(x-10)+5=

since we have a square root the quantity under it must equal or greater than zero hence

x-10>=0=>x>=10

So the domain is [10,+oo) (where x gets its values)

To find the range eg where y gets its values we notice that

y-5=sqrt(x-10)>=0=>y-5>=0=>y>=5 hence the range is

[5,+oo)