How do you find the domain and range of $y = \sqrt{x - 4}$ $y=sqrt(x-4)$ ?

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Answer 1 · 2015-08-17T15:55:05

Since the argument must be non-negative $x \geq 4$ $x>=4$ .

Since there is no upper limit the domain of $x$ $x$ is $[4, \infty)$ $[4,oo)$

When $x = 4 \to y = 0$ $x=4->y=0$ .
Again there is no upper limit, so the range of $y$ $y$ is $[0, \infty)$ $[0,oo)$

How do you find the domain and range of y=√x−4y=sqrt(x-4)?