How do you find the domain and range of y=x^2 - 5?

1 Answer
Oct 24, 2017

-oo < x < oo
y >= -5

Explanation:

The domain is the set of x values a function can take to give a real y value, which in the function y = x^2 -5 is simply any x value. For instance, when x=-6 then y = 36-5 = 31. Similarly, when x=1000, then y=1000000-5=999995.

Therefore, -oo < x < oo, x in RR.

However, for x in RR, x^2 >= 0. In other words, a square number is always positive (greater than 0), so a square number minus five must be always greater than minus five. So,

x^2 >= 0

:.

x^2 - 5 >= -5

:.

y >= -5

This is the range of the function, which is defined as the set of y values that can be taken by the function. You'll never find a (real) solution for anything less than y = -5, for which x = 0.