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How do you find the domain for $\frac{1}{x + 3}$ $1/(x+3)$ ?

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Konstantinos Michailidis

Jun 6, 2016

The domain is all the values of real x for which $x + 3 \neq 0$ $x+3!=0$ hence

$D = R - {- 3}$ $D=R-{-3}$

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