How do you find the domain of $(3x-6)/ (sqrt(2x+1) - 3)?$

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Answer 1 · 2015-04-15T03:51:14

The function is defined if

$(2x + 1) > 0 -> 2x > -1 -> x > -1/2$

The domain of $x$ is $(-1/2, +oo)$

Check: $if x = 1 -> (2x + 1) = 3 > 0$

How do you find the domain of (3x-6)/ (sqrt(2x+1) - 3)?(3x-6)/ (sqrt(2x+1) - 3)?