How do you find the domain of $4 \sqrt{x - 3}$ $4sqrt(x-3)$ ?

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Answer 1 · 2017-08-29T23:38:59

$Dom (f) = x \geq 3$ $"Dom"(f) = x ≥ 3$

For any radical function defined over the real plane, we need to make sure that the radical is greater than or equal to zero.

$x - 3 \geq 0$ $x-3 ≥ 0$

$x \geq 3$ $x ≥ 3$

How do you find the domain of 4sqrt(x-3)4√x−34sqrt(x-3)?