How do you find the domain of 5/(x sqrt (x+2))5xx+2?

1 Answer
Jun 16, 2018

The domain is x in (-2,0)uu(0,+oo)x(2,0)(0,+)

Explanation:

The denominator must be !=00

Therefore,

x!=0x0

and

x+2!=0x+20, =>, x!=-2x2

and for the square root sign

x+2>0x+2>0, =>, x > -2x>2

Finally. the domain is x in (-2,0)uu(0,+oo)x(2,0)(0,+)

graph{5/(xsqrt(x+2)) [-20.28, 20.27, -10.14, 10.14]}