How do you find the domain of $f(x) =2sqrt(3x + 4) - 5$ ?

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Answer 1 · 2016-12-19T11:26:39

Domain: $x>= -4/3$ , Range: $f(x) >= -5$

Domain (possible value of x) : $3x+4 >=0 or 3x >= -4 or x>= -4/3$ since under root can not be negative number.

Range (possible value of f(x)) : $f(x)> =2*0 -5 >=-5$
Domain: $x>= -4/3$ , Range: $f(x) >=-5$
graph{2(3x+4)^0.5-5 [-20, 20, -10, 10]} [Ans]

How do you find the domain of f(x) =2sqrt(3x + 4) - 5f(x) =2sqrt(3x + 4) - 5?