How do you find the domain of $f (x) = \frac{2 x^{2}}{x^{2} - 9}$ $f(x)=(2x^2)/(x^2-9)$ ?

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How do you find the domain of $f (x) = \frac{2 x^{2}}{x^{2} - 9}$ $f(x)=(2x^2)/(x^2-9)$ ?

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Answer 1 · 2017-05-20T15:45:30

$x inRR,x!=+-3$

Explanation:

The domain is defined for all values of x except values that make the denominator of f(x) equal to zero as this would make f(x) $color(blue)"undefined"$ Equating the denominator to zero and solving gives the values that x cannot be.

$"solve " x^2-9=0rArr(x-3)(x+3)=0$

$rArrx=+-3larrcolor(red)" excluded values"$

$rArr"domain is " x inRR,x!=+-3$

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How do you find the domain of $f (x) = \frac{2 x^{2}}{x^{2} - 9}$ $f(x)=(2x^2)/(x^2-9)$ ?

1 Answer

Explanation:

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How do you find the domain of f(x)=(2x^2)/(x^2-9)f(x)=2x2x2−9f(x)=(2x^2)/(x^2-9)?

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How do you find the domain of $f (x) = \frac{2 x^{2}}{x^{2} - 9}$ $f(x)=(2x^2)/(x^2-9)$ ?