How do you find the domain of f(x)=(2x)/((x-2)(x+3))f(x)=2x(x2)(x+3)?

2 Answers
Jul 18, 2017

The denominatos can't be zero.

Explanation:

The only contraint is : (x-2)(x+3)!=0 iff x!=2 and x!=-3(x2)(x+3)0x2andx3

so the domain is then D=x in RR-{-3,2}

Jul 18, 2017

x inRR,x!=-3,2

Explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be.

"solve " (x-2)(x+3)=0

rArrx=-3" and " x=2larrcolor(red)" are excluded values"

"domain is " x inRR,x!=-3,2