How do you find the domain of $f(x) =3sqrt(6x + 42)$ ?

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Answer 1 · 2018-03-23T15:38:01

$[-7,+oo)$

$"the domain is determined by the radical"$

$"that is "$

$6x+42>=0rArrx>=-7$

$rArr" domain is "[-7,+oo)$
graph{3sqrt(6x+42) [-10, 10, -5, 5]}

How do you find the domain of f(x) =3sqrt(6x + 42)f(x) =3sqrt(6x + 42)?