How do you find the domain of $f (x) = \frac{3 x^{2}}{x^{2} - 49}$ $f(x) = (3x^2)/(x^2-49)$ ?

Question

How do you find the domain of $f (x) = \frac{3 x^{2}}{x^{2} - 49}$ $f(x) = (3x^2)/(x^2-49)$ ?

1 Answer

Impact of this question

2299 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-02T14:18:00

$"domain " x inRR,x!=+-7$

Explanation:

The denominator of f(x) cannot be zero as this would make f(x) $color(blue)"undefined".$ Equating the denominator to zero and solving gives the values that x cannot be.

$"solve " x^2-49=0rArr(x-7)(x+7)=0$

$rArrx=-7" and " x=7larrcolor(red)" are excluded values"$

$"domain " x inRR,x!=+-7$

Science

Math

Humanities

... and beyond

How do you find the domain of $f (x) = \frac{3 x^{2}}{x^{2} - 49}$ $f(x) = (3x^2)/(x^2-49)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the domain of f(x) = (3x^2)/(x^2-49)f(x)=3x2x2−49f(x) = (3x^2)/(x^2-49)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the domain of $f (x) = \frac{3 x^{2}}{x^{2} - 49}$ $f(x) = (3x^2)/(x^2-49)$ ?