How do you find the domain of f(x)=(-3x^2)/(x^2+4x-45)f(x)=3x2x2+4x45?

1 Answer
Aug 5, 2016

Domain: all Real values except (-9)(9) and (+5)(+5)

Explanation:

f(x)=(-3x^2)/(x^2+4x-45)f(x)=3x2x2+4x45
color(white)("XXX")XXXwill be defined for all Real values of xx
color(white)("XXX")XXXexcept those values which cause the denominator to be equal to zero.

That is the Domain will be all RR
except when
color(white)("XXX")x^2+4x-45=0

Factoring:
color(white)("XXX")(x+9)(x-5)=0

So the Domain of f(x) is
color(white)("XXX")RR-{-9,+5}