How do you find the domain of f(x)=(x^2-9)/sqrt(x^2-4)?
1 Answer
Jan 20, 2018
Explanation:
x^2-9" is defined for all real values of x"
"the denominator cannot equal zero as this would make"
"f(x) undefined"
rArrx^2-4!=0
rArr(x-2)(x+2)!=0
rArrx!=+-2
"also "x^2-4>0
rArrx<-2,x>2
"domain is "(-oo,-2)uu(2,+oo)
graph{(x^2-9)/(sqrt(x^2-4)) [-10, 10, -5, 5]}