How do you find the domain of $f(x) =( x - 2) / (x^2- 16)$ ?

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Answer 1 · 2015-11-05T18:27:46

${x in RR : x!= -4 and x!= 4}$

Set the denominator equal to 0.

$x^2 - 16 = 0$

Solve for x.

// add 16 to both sides

$x^2 = 16$

// root both sides

$x = 4, -4$

The domain is 4, -4 as the denominator cannot be 0. So therefore, the domain can be stated as ${x in RR : x!= -4 and x!= 4}$

How do you find the domain of f(x) =( x - 2) / (x^2- 16)f(x) =( x - 2) / (x^2- 16)?