How do you find the domain of f(x)=x/(6x^2+13x-5)?

1 Answer
Jun 20, 2016

Domain (value of x) is any real value except x = 1/3 or x = -2/5

Explanation:

Domain is the value of x in the function. Here the denomintor must not be zero. 6x^2+13x-5 !=0 or 6x^2+15x-2x-5 != 0 or 3x(2x+5)-1(2x+5) !=0 or (3x-1)(2x+5) !=0 or x !=1/3 and x !=-5/2 :.Domain (value of x) is any real value except x = 1/3 or x = -2/5 [Ans]