How do you find the domain of $f(x)=x/(x^2+1)$ ?

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Answer 1 · 2017-04-16T10:26:13

The domain is $=RR$

The denominator is $(x^2+1)$

$AA x in RR, (x^2+1)>0$

So, the domain of $f(x)$ is

$D_f(x)=RR$

graph{x/(x^2+1) [-10, 10, -5, 5]}

How do you find the domain of f(x)=x/(x^2+1)f(x)=x/(x^2+1)?