How do you find the domain of $g(t)= sqrt(1-2^t)$ ?

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Answer 1 · 2015-04-16T11:07:50

Assuming we are restricted to Real numbers:

$2^t > 1$ for all $t>0$

$g(t)$ is not defined for values of $(1-2^t) < 0$

That is
$g(t)$ is only defined if $(1-2^t)>=0$
or
$t<=1$

The Domain of $g(t)$ is $t epsilon (-oo,1]$

How do you find the domain of g(t)= sqrt(1-2^t)g(t)= sqrt(1-2^t)?