Question

How do you find the domain of `(x^2-x-12)^-(1/4)`?

Answer 1

The domain is `D=(-oo;-3)uu(4;+oo)`

Proof

This function can be written as `y=1/(root(4)(x^2-x-12))`.
so the domain is this subset of `RR` where `x^2-x-12>0`

After solving given inequality you get the answer. It can also be seen on a graph graph{x^2-x-12 [-13.12, 18.05, -12.99, 2.59]}