How do you find the domain of $y = \sqrt{x + 4}$ $y =sqrt(x + 4)$ ?

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Answer 1 · 2017-05-17T17:28:01

Since the domain talks about real numbers only, we need to find when the $\sqrt \geq 0$ $√ ≥ 0$ .

$0 \leq x + 4$ $0 ≤ x+ 4$

$- 4 \leq x$ $-4 ≤ x$

Therefore , the domain is ${x| x ≥ -4, x in RR}$ .

Hopefully this helps!

How do you find the domain of y =sqrt(x + 4)y=√x+4y =sqrt(x + 4)?