Question

How do you find the end behavior of `y=-3(x-2)(x+2)^2(x-3)^2`?

Answer 1

If you expand y you will get the following

`y=-3x^5+12x^4+21x^3-102x^2-36x+216`

Explanation:

Now if we let x^5 be a common factor like that

`y=x^5(-3+12x^4/x^5+21x^3/x^5-102x^2/x^5-36x/x^5+216/x^5)`

As `x->+oo ,y->-oo` and `x->-oo ,y->+oo`