How do you find the exact value for (5tan60°) / cos30°?

1 Answer
Jun 8, 2015

You can do this without a calculator and with few manipulations.

(5tan60^o)/(cos30^o) = (5sin60^o)/[(cos30^o)(cos60^o)]

but

sin(pi/2 - x) = cosx

Therefore:

sin(90^o - overbrace(30^o)^x) = sin60^o = cos30^o

=> (5cancel(sin60^o))/[cancel((cos30^o))(cos60^o)]

= (5cancel(sqrt3/2))/(cancel(sqrt3/2)*1/2)

= 10