How do you find the exact value of $\frac{1}{cot (\frac{π}{4})} - \frac{2}{csc (\frac{π}{6})}$ $1/[cot(pi/4)] - 2/[csc(pi/6)]$ ?

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Answer 1 · 2015-06-08T17:46:46

$\frac{1}{cot (\frac{π}{4})} = tan (\frac{π}{4})$ $1/cot (pi/4) = tan(pi/4)$ = 1

$csc (\frac{π}{6}) = \frac{1}{sin (\frac{π}{6})} = \frac{1}{\frac{1}{2}} = 2$ $csc (pi/6) = 1/sin (pi/6) = 1/(1/2) = 2$

$\frac{2}{csc (\frac{π}{6})} = \frac{2}{2} = 1$ $2/csc(pi/6) = 2/2 = 1$

$\frac{1}{cot (\frac{π}{4})} - \frac{2}{csc (\frac{π}{4})} = 1 - 1 = 0$ $1/cot (pi/4) - 2/csc (pi/4) = 1 - 1 = 0$

How do you find the exact value of 1cot(π4)−2csc(π6)1/[cot(pi/4)] - 2/[csc(pi/6)]?