How do you find the exact value of $arcsin(1) - arcsin(-1)$ ?

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Answer 1 · 2016-10-18T12:59:33

$- pi$

Use the trig unit circle:
$arcsin (1) --> pi/2$
$arcsin (-1) --> (3pi)/2$
$arcsin (1) - arcsin (-1) = pi/2 - (3pi)/2 = - (2pi)/2 = - pi$

How do you find the exact value of arcsin(1) - arcsin(-1)arcsin(1) - arcsin(-1)?