How do you find the exact value of $arcsin(sin((2pi)/3))$ ?

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Answer 1 · 2017-03-02T16:25:40

$arcsin(sin((2pi)/3))=(2pi)/3$

By definition if $sinA=x$ , $arcsinx=A$ ,

and substituting $x$ for $sinA$ in $arcsinx=A$

$arcsin(sinA)=A$ and hence

$arcsin(sin((2pi)/3))=(2pi)/3$

How do you find the exact value of arcsin(sin((2pi)/3))arcsin(sin((2pi)/3))?