How do you find the exact value of $cot^-1(cot((2pi)/3))$ ?

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Answer 1 · 2017-06-21T10:58:36

$cot^-1(cot ((2pi)/3)) = ((2pi)/3)$

Let $cot^-1(cot ((2pi)/3)) = theta$ , then

$cot theta = cot ((2pi)/3) :. theta = ((2pi)/3) :.$

$cot^-1(cot ((2pi)/3)) = ((2pi)/3)$ [Ans]

Answer 2 · 2017-06-21T10:59:30

Assuming $color(blue)(cot^-1)$ is defined as a function with a range of $color(blue)([0,pi))$
then $cot^-1(cot((2pi)/3))=color(red)((2pi)/3)$

How do you find the exact value of cot^-1(cot((2pi)/3))cot^-1(cot((2pi)/3))?