How do you find the exact value of $cot^-1(-sqrt3)$ ?

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Answer 1 · 2017-06-11T10:08:29

$cot^(-1)(-sqrt3)=-pi/6$

The range for $cot^(-1)x$ is from $-pi/2$ to $pi/2$

As $cot(-pi/6)=-sqrt3$

$cot^(-1)(-sqrt3)=-pi/6$

How do you find the exact value of cot^-1(-sqrt3)cot^-1(-sqrt3)?