How do you find the exact value of ${csc}^{- 1} (- 1)$ $csc^-1(-1)$ ?

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Answer 1 · 2016-12-01T17:09:08

${csc}^{- 1} (- 1) = - \frac{π}{2}$ $csc^(-1)(-1)=-pi/2$

${csc}^{- 1} (- 1)$ $csc^(-1)(-1)$ is the angle whose cosecant ratio is $- 1$ $-1$ , i.e. whose sine ratio is $- 1$ $-1$ .

As $sin (- \frac{π}{2}) = - 1$ $sin(-pi/2)=-1$ , hence

${csc}^{- 1} (- 1) = - \frac{π}{2}$ $csc^(-1)(-1)=-pi/2$

How do you find the exact value of csc^-1(-1)csc−1(−1)csc^-1(-1)?