How do you find the exact value of ${ln e}^{2} + {ln e}^{5}$ $ln e^2+lne^5$ ?

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Answer 1 · 2017-01-11T06:26:56

${ln e}^{2} + {ln e}^{5} = 7$ $lne^2+lne^5 = 7$

Remember: ${ln e}^{a} = a$ $lne^a = a$

$:. lne^2+lne^5 = 2+5 =7$

Alternatively you could approach this problem as follows:

$lne^2+lne^5 = ln (e^2 xx e^5)$

$=lne^7 = 7$

How do you find the exact value of ln e^2+lne^5lne2+lne5ln e^2+lne^5?