How do you find the exact value of log_2 root4 8?

1 Answer
Oct 1, 2017

3/4

Explanation:

"using the "color(blue)"law of logarithms"

•color(white)(x)log_bx=nhArrx=b^n

rArrlog_2(root(4)(8))=n

rArrroot(4)(8)=2^n

"using the "color(blue)"law of exponents"

•color(white)(x)a^(m/n)=root(n)(a^m)

rArrroot(4)(2^3)=2^(3/4)=2^n

"since the bases on both sides are 2 we can equate"
"the exponents"

rArrn=3/4

rArrlog_2root(4)(8)=3/4