How do you find the exact value of log_2 root4 8?
1 Answer
Oct 1, 2017
Explanation:
"using the "color(blue)"law of logarithms"
•color(white)(x)log_bx=nhArrx=b^n
rArrlog_2(root(4)(8))=n
rArrroot(4)(8)=2^n
"using the "color(blue)"law of exponents"
•color(white)(x)a^(m/n)=root(n)(a^m)
rArrroot(4)(2^3)=2^(3/4)=2^n
"since the bases on both sides are 2 we can equate"
"the exponents"
rArrn=3/4
rArrlog_2root(4)(8)=3/4