How do you find the exact value of $sin^-1 (sqrt2/2)$ ?

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Answer 1 · 2017-04-14T11:19:15

$sin^-1 (sqrt2/2) = pi/4$

Let $sin^-1 (sqrt2/2) = theta$ , then $sin theta = sqrt2/2$ . We know $sin (pi/4) = sqrt2/2 :. theta = pi/4 or sin^-1 (sqrt2/2) = pi/4$ [Ans]

How do you find the exact value of sin^-1 (sqrt2/2)sin^-1 (sqrt2/2)?