Question

How do you find the exact value of `sin^-1 (sqrt2/2)`?

Answer 1

`sin^-1 (sqrt2/2) = pi/4`

Explanation:

Let `sin^-1 (sqrt2/2) = theta` , then `sin theta = sqrt2/2`. We know `sin (pi/4) = sqrt2/2 :. theta = pi/4 or sin^-1 (sqrt2/2) = pi/4` [Ans]