How do you find the exact value of $sin^-1 (sqrt3/2)$ ?

Question

3682 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-07T14:55:01

$pi/3 = 60º$

$sqrt(3)/2 = sin x$

$x = pi/3 + 2kpi$ or $x = pi - pi/3 + 2kpi$ , for all $k \in mathbb{Z}$

But the function $y = arcsin x$ returns a single angle in the interval $[-pi/2, pi/2]$ .

How do you find the exact value of sin^-1 (sqrt3/2)sin^-1 (sqrt3/2)?