How do you find the exact value of $sin60°cos30° + sin30°cos60°$ ?

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Answer 1 · 2015-04-26T02:08:40

$30^o " and " 60^o "are angles of one of the standard triangles"$

$sin(30^o) = 1/2$

$cos(30^o) = sqrt(3)/2$

$sin(60^o) = sqrt(3)/2$

$cos(60^o) = 1/2$

So
$sin(60^o)*cos(30^o) + sin(30^o)*cos(60^o)$

$=(sqrt3/2)(sqrt3/2) +(1/2)(1/2) = 3/4 +1/4$

$=1$

How do you find the exact value of sin60°cos30° + sin30°cos60°sin60°cos30° + sin30°cos60°?