How do you find the exact value of $tan ({tan}^{- 1} 25)$ $tan(tan^-1 25)$ ?

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Answer 1 · 2017-02-07T05:01:21

$25^{o}$ $25^o$

Let say $θ = tan ({tan}^{- 1} 25)$ $theta =tan(tan^-1 25)$

${tan}^{- 1} (θ) = {tan}^{- 1} (25)$ $tan^-1 (theta) = tan^-1 (25)$

$θ = 25$ $theta = 25$

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