Question

How do you find the exact values of `arccos(sqrt3/2)`?

Answer 1

`pi/6, (5pi)/6`

Explanation:

Trig Table of special arcs gives -->
`cos x = sqrt3/2` --> arc `x = pi/6`
Unit circle gives another arc that has the same cos value:
arc `x = (5pi)/6`
Answers for `(0, 2pi)`:
`pi/6, (5pi)/6`