Question

How do you find the indefinite integral of `int -(35x^(2/5))/5dx`?

Answer 1

`-5x^(7/5)+c`

Explanation:

`int-35x^(2/5)dx = -35/5intx^(2/5)dx`

`= -35/5 {x^(7/5)/(7/5)} +c= -35/5 xx 5/7.x^(7/5)+c`

`=-5x^(7/5)+c`