Question

How do you find the integral from 0 to 3 of `(1/2 x - 1) dx`?

Answer 1

`int_0^3(1/2x-1)dx = int_0^3(1/4x^2-x)dx`

We have :

`1/2[(1/2x^2-2x)]_0^3`

Therefore :

`1/2(9/2-6)`

`=-3/4`