Question

How do you find the integral of `6x ln x dx`?

Answer 1

I found: `3x^2[ln(x)-1/2]+c`

Explanation:

I would try By Parts:
`int6xln(x)dx=6x^2/2ln(x)-int6x^cancel(2)/2*1/cancel(x)dx=`
`=3x^2ln(x)-int3xdx=`
`=3x^2ln(x)-3x^2/2+c=`
`=3x^2[ln(x)-1/2]+c`