How do you find the integral of $(cos^4 x sin x) dx$ from $[0, pi/3]$ ?

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Answer 1 · 2015-04-17T03:50:31

Have a look:
$intcos^4(x)sin(x)dx=$
but: $d[cos(x)]=-sin(x)dx$
$=-intcos^4(x)d[cos(x)]=$
$=-cos^5(x)/5|_0^(pi/3)$ $=31/160$

How do you find the integral of (cos^4 x sin x) dx(cos^4 x sin x) dx from [0, pi/3][0, pi/3]?