How do you find the inverse of the function $y=log(x-2)$ ?

Question

6814 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-19T23:32:34

$f^-1(x) = 10^x + 2$

Switch the $x$ and $y$ values and solve for $y$ .

$y = log(x- 2)$

$x = log(y - 2)$

$10^x = y- 2$

$y = 10^x + 2$

Hopefully this helps!

How do you find the inverse of the function y=log(x-2)y=log(x-2)?