How do you find the inverse of $y=ln(x+1)$ ?

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Answer 1 · 2016-07-09T04:17:23

The inverse is found algebraically by switching the x and y values.

$y = ln(x + 1)$

$x = ln(y + 1)$

$e^x = y + 1$

$y = e^x - 1$

Practice exercises:

$y = 2^(x - 5)$

$y = (x - 2)^3 + 6$

$y = root(4)(x^2 + 7) - 1$

Hopefully this helps, and good luck!

How do you find the inverse of y=ln(x+1)y=ln(x+1)?