Question

How do you find the next two terms of the geometric sequence `81, 108, 144,...`?

Answer 1

192; 256

Explanation:

`a_(i+1)=a_ixxr`

`=>r=(a_(i+1))/a_i = 108/81 = 144/108 = 4/3`

`a_1=81`
`a_2=81xx4/3= 108`
`a_3=108xx4/3=144`
`a_4=144xx4/3= 192`
`a_5=192xx4/3= 256`

`a_n=81xx(4/3)^(n-1)`