How do you find the phase shift of $y = sin (θ - 3 \frac{π}{4})$ $y=sin(theta-3 pi/4)$ ?

Question

5129 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-02T14:21:53

     
 Horizontal shift =3pi/4

$y = sin (θ - 3 \frac{π}{4})$ $y=sin(theta-3pi/4)$

enter image source here
we have
$a = 1$ $a=1$
$b = 1$ $b=1$
$c = 3 \frac{π}{4}$ $c=3pi/4$

       A phase shift is nothing but horizontal shift.

 Horizontal shift =3pi/4

How do you find the phase shift of y=sin(θ−3π4)y=sin(theta-3 pi/4)?